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April 25, 2014

April 25, 2014

Posted by **John** on Tuesday, September 17, 2013 at 2:13am.

Ex: log cot 0.1690 and log sin (25degrees 22min)

log sin (25+22/60)

= log sin 22.3666666667

= sin 0.38053243281

= (-0.41960832236)

Is there a simpler way to do these?

I get confused with finding the angles using logarithms

- Logarithms -
**Steve**, Tuesday, September 17, 2013 at 4:09amnope. to take the log, ya gotta find the sine first.

Of course, if you have a decent calculator, that means you just have to

enter 22/60+22=

then press deg sin log

- Logarithms -
**John**, Tuesday, September 17, 2013 at 6:40amBut how can you do the inverse? such as

Log cot B 0.1690 = what angle?

should find the cot first then the log?

- Logarithms -
**Steve**, Tuesday, September 17, 2013 at 2:11pmyour expression makes no sense.

If you mean

log cot B = 0.1690

then that means

cot B = 10^.1690 = 1.4757

B = cot^{-1}1.4757 = .5955

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