Posted by Anonymous on Monday, September 16, 2013 at 11:51pm.
(4x)^2/3=(30x+4)^1/3
please explain=)

math  Jai, Tuesday, September 17, 2013 at 12:21am
(4x)^(2/3) = (30x+4)^(1/3)
To do this, note that it's much easier to work with whole number exponents. This we raise both side terms by 3, so that the denominator 3 will be cancelled:
(4x)^(2/3 * 3) = (30x+4)^(1/3 * 3)
(4x)^2 = (30x+4)^1
16x^2 = 30x + 4
Solving for x,
8x^2  15x  2 = 0
(8x + 1)(x  2) = 0
x = 2
x = 1/8
Then we check by substituting these x values to the original equation:
i. x = 2
(4x)^(2/3) = (30x+4)^(1/3)
(4*2)^(2/3) = (30*2+4)^(1/3)
(8)^(2/3) = 64^(1/3)
2^2 = 4
4 = 4
Thus x is indeed equal to 2.
ii. x = 1/8
(4x)^(2/3) = (30x+4)^(1/3)
(4*(1/8))^(2/3) = (30*(1/8)+4)^(1/3)
(1/2)^(2/3) = (15/4 + 16/4)^(1/3)
(1/4)^(1/3) = (1/4)^(1/3)
Thus x is also equal to 1/8.
Hope this helps~ :3

math  sara, Wednesday, September 18, 2013 at 2:05am
i didn't get how 16x^2 turned into 8x^2
16x^2 = 30x + 4
Solving for x,
8x^2  15x  2 = 0
Answer This Question
Related Questions
 math, algebra  can someone correct this for me or help me. 6x^2y^3+ 9x^2y^3 ...
 ALGEBRA  If I divide 28x^330x^267x21 BY 7x+3...will I get 4x^210x21? THEN ...
 Algebra  I need help trying to put the correct vocabulary words when solving ...
 Algebra: factoring  I need to find the value of x. 9x^3 + 9x = 30x^2 It's ...
 Algebra help/ look over please  Can you please look over these and let me know ...
 Algebra  I need help trying to put the correct vocabulary words when solving ...
 math  We did this qs in class so we change the equation into the vertex form ...
 math  For f(x) and g(x) given below, find the following, f(x) = (x1)^5, g(x)=1...
 Polynomials  The circular area of the drum is (9x^2+30x+25)pi. What is the ...
 Algebra  Convert the simplified parabolic equation y=3x^230x7 to standard ...
More Related Questions