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September 20, 2014

September 20, 2014

Posted by **Anonymous** on Monday, September 16, 2013 at 3:44pm.

- Geometry -
**Reiny**, Monday, September 16, 2013 at 4:51pmlet the width be 2x and the length be 3x

Area = 6x^2

perimeter = 10

10x/6x^2 = 5/9

30x^2 = 90x

divide by 30 and factor

x(x-3) = 0

x = 0 or x = 3, x=0 is not admissable (we have to have some sort of a width)

the width is 6 and the length is 9

check:

area = 54

perimeter = 30

what is 30/54 ??

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