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A police car is traveling at a velocity of 19.0 m/s due north, when a car zooms by at a constant velocity of 49.0 m/s due north. After a reaction time 0.600 s the policeman begins to pursue the speeder with an acceleration of 6.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?

  • Physics - ,

    19t + 0.5a*t^2 = 49t + 49*0.6
    19t + 0.5*6*t^2 = 49t + 29.4
    3t^2 - 30t - 29.4 = 0
    t = 10.9 s.

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