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December 21, 2014

December 21, 2014

Posted by **Marian** on Monday, September 16, 2013 at 11:21am.

True or false?

- MATHS -
**Steve**, Monday, September 16, 2013 at 2:22pmif you have limit as x->2, then TRUE

- MATHS -
**Marian**, Monday, September 16, 2013 at 4:38pmi have limit x->0

- MATHS -
**Steve**, Monday, September 16, 2013 at 5:27pmOh, my bad. I read it as sqrt(4-x^2)

If x->0, then since x^4 and x^2 are both 0, then limit is also 0, so TRUE.

so, right answer, wrong reason. :-)

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