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April 19, 2014

Homework Help: calculus

Posted by ms on Monday, September 16, 2013 at 4:10am.

Find circumference of the circle r=2acos theta.
s= Int (0 to 2pi) of Sqrt(4a^2cos^2 theta+4a^2sin^2 theta)d theta
=Int (0 to 2pi)2a*Int theta d theta
=2a(2pi-0)=4a*pi
Book shows 2a*pi. Am I wrong somewhere?

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