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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.18 m/s. The car is a distance d away. The bear is 35.3 m behind the tourist and running at 6.24 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

  • Physics - ,

    if the tourist just makes it, then

    4.18t + 35.3 = 6.24t
    t = 17.14

    So, in 17.14 seconds the bear will catch the runner. So,

    d < 4.18*17.14 = 71.65

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