Before the final exam, a student has test scores of 72, 80, 65, 78, and 60. If the final exam counts as one-third of the final grade, what score must the student receive in order to have a final average of 76 percent?

Thanks!!

Why did the scarecrow become a Math genius?

Because he was outstanding in his field!

To determine the score needed on the final exam, let's break it down.

The total number of test scores is 5 and each score carries equal weight. Since the final exam counts as one-third of the final grade, it will also carry one-third of the overall weight. That means the previous test scores cover the remaining two-thirds of the weight.

Now, we can calculate the weighted average to find the required score on the final exam.

(72 + 80 + 65 + 78 + 60) * 2/3 + Final Exam Score * 1/3 = 76

Adding up the previous test scores gives us 355.

(355 * 2/3) + Final Exam Score * 1/3 = 76

(355 * 2/3) = 76 - Final Exam Score * 1/3

(355 * 2/3) = 76 - (Final Exam Score * 1/3)

(355 * 2/3) - 76 = - (Final Exam Score * 1/3)

Final Exam Score * 1/3 = (355 * 2/3) - 76

Final Exam Score = [(355 * 2/3) - 76] / (1/3)

Final Exam Score = [(355 * 2) - 76] / (1/3)

Final Exam Score = (710 - 76) / (1/3)

Final Exam Score = 634 / (1/3)

Final Exam Score = 634 * 3

Final Exam Score = 1902

So, the student needs to receive a score of 1902 on the final exam. Just kidding! That would be more than impressive.

The real score needed would be (710 - 76) / (1/3) = 856.

Good luck, and remember to keep a good sense of humor while studying!

To find the score the student must receive on the final exam, we can use the following equation:

(average of the previous test scores * 2/3) + (score on the final exam * 1/3) = final average

Let's plug in the given information:

( (72 + 80 + 65 + 78 + 60) / 5 * 2/3 ) + ( score on the final exam * 1/3 ) = 76

First, calculate the average of the previous test scores:

(72 + 80 + 65 + 78 + 60) / 5 = 71

Now, substitute the values back into the equation:

(71 * 2/3) + ( score on the final exam * 1/3 ) = 76

Multiply 71 by 2/3:

(71 * 2/3) = 47.33

Subtract 47.33 from both sides of the equation:

(score on the final exam * 1/3 ) = 76 - 47.33

Simplify:

(score on the final exam * 1/3 ) = 28.67

Multiply both sides of the equation by 3:

score on the final exam = 28.67 * 3

score on the final exam ≈ 86

Therefore, the student must receive a score of approximately 86 on the final exam in order to have a final average of 76 percent.

To find out what score the student must receive on the final exam in order to have a final average of 76 percent, we can set up an equation.

Let's denote the score on the final exam as "x".

The final average is calculated by taking the sum of all the scores and dividing it by the total number of scores:

Final average = (Sum of all test scores + Final exam score) / (Total number of scores + 1)

So, in this case, the equation becomes:

76 = (72 + 80 + 65 + 78 + 60 + x) / (5 + 1)

Now, let's solve for "x".

Multiply both sides of the equation by (5 + 1) to eliminate the denominator:

76 * (5 + 1) = 72 + 80 + 65 + 78 + 60 + x

Combine like terms:

456 = 355 + x

Subtract 355 from both sides:

456 - 355 = x

101 = x

Therefore, the student must score 101 on their final exam in order to have a final average of 76 percent.

Test Average = (72+80+65+78+60)/5 = 71

Test Points = 2/3 * 71 = 47.33

47.33 + S/3 = 76
142 + S = 228
S = 86 = Final Exam score.