Posted by **Jackie ** on Saturday, September 14, 2013 at 6:57pm.

f(x)= 1/x^2-8x-9

g(x)= 1/x^2+3x+2

- math -
**Jai**, Saturday, September 14, 2013 at 7:04pm
What is required to find? :3

- math -
**Jackie **, Saturday, September 14, 2013 at 7:05pm
Domain

- math -
**Jai**, Saturday, September 14, 2013 at 7:16pm
Domain of what?

If the required is their individual domains:

1. For f(x) = 1/(x^2 - 8x - 9)

Note that domain is the set of all possible values of x. In the function, note that the denominator must not be equal to zero because 1/0 is infinity. Therefore, we find the values of x, which the denominator will be zero and restrict the domain to those values:

f(x) = 1/(x^2 - 8x - 9)

f(x) = 1/(x-9)(x+1)

Thus, x is all real numbers except -1 and 9.

2. For g(x) = 1/(x^2 + 3x + 2)

The procedure is pretty much the same. We find the values of x which will make the denominator zero:

g(x) = 1/(x^2 + 3x + 2)

g(x) = 1/(x+1)(x+2)

Thus, x is all real number except -1 and -2.

Hope this helps~ :3

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