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March 29, 2017

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Solve for x.

-3x^2+8=-4

  • PreCal - ,

    -3x^2 = -12
    x^2 = 4
    x = ±2

  • PreCal - ,

    thanks and what about this one ?
    Simplify the expression

    (3x^-1y^2)^3(5x^2y)0

    I'm getting confused because of the negative exponent

  • PreCal - ,

    anything^0 = 1, so we just have

    (3x^-1y^2)^3 = 27 x^-3 y^6 = 27y^6/x^3

    negative exponents indicate a swap between numerator and denominator

    x^-3 = 1/x^3

    1/x^-3 = x^3

    recall that x^a/x^b = x^(a-b)

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