Posted by **Anonymous ** on Saturday, September 14, 2013 at 6:36pm.

Solve for x.

-3x^2+8=-4

- PreCal -
**Steve**, Saturday, September 14, 2013 at 6:46pm
-3x^2 = -12

x^2 = 4

x = ±2

- PreCal -
**Anonymous **, Saturday, September 14, 2013 at 6:49pm
thanks and what about this one ?

Simplify the expression

(3x^-1y^2)^3(5x^2y)0

I'm getting confused because of the negative exponent

- PreCal -
**Steve**, Saturday, September 14, 2013 at 6:56pm
anything^0 = 1, so we just have

(3x^-1y^2)^3 = 27 x^-3 y^6 = 27y^6/x^3

negative exponents indicate a swap between numerator and denominator

x^-3 = 1/x^3

1/x^-3 = x^3

recall that x^a/x^b = x^(a-b)

## Answer This Question

## Related Questions

- Precal - Solve for x 9^x - 4 * 3^x +3=0 I know the 9^x = (3^x)^2
- Precal - Solve for x 9^(x^2) = 3^(-5x-2)
- precal - Solve for y: (y-(10/y))^2+6(y-(10/y))-27=0
- precal - solve for x: (x^2-2x)^2 -11(x^2-2x)+24
- PreCal - Solve The Inequality 0 < -9x/x-x^2
- precal - solve by subsituting 5x+4y=7 x-3y=9
- precal - solve for x: 4sin^2x= 4cosx+1
- precal - solve for x: 4sin^2x= 4cosx+1
- precal - solve for x: 4sin^2x= 4cosx+1
- PreCal - absolute values solve for "x" 2|5x-5|+4=20

More Related Questions