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February 1, 2015

February 1, 2015

Posted by **steph** on Saturday, September 14, 2013 at 2:43pm.

- physics -
**Steve**, Saturday, September 14, 2013 at 4:05pmview the setup from the side, with the line joining the light source and the center of the ball perpendicular to the wall.

Then, if the light is x cm away from the wall, using similar triangles,

x/29.5 = (x-127)/12.3

x = 217.8 cm

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