Posted by Cece on Saturday, September 14, 2013 at 2:28pm.
system of equations:
solve the following system of operations using matrices (row operations)
{5x + y + z + w = 5}
{x  2y + 2z 3w = 4}

college math  Steve, Saturday, September 14, 2013 at 2:29pm
2 equations
4 unknowns
no single solution.

college math  Cece, Saturday, September 14, 2013 at 2:40pm
I need more than that. What are the values of "x"
I worked out the values of "y" to be:
y = (15/11) + (9/11z)  (16/11w), but I could be wrong

college math  Steve, Saturday, September 14, 2013 at 2:43pm
oh, well, if that's the kind of solution you want, then it's ok.
Eliminating x, I get
5x+y+z+w = 5
5x10y+10z15w = 20
11y9z+16w = 15
so your answer looks good to me.

college math  Cece, Saturday, September 14, 2013 at 3:08pm
so are you saying that "x" is 15?

college math  Steve, Saturday, September 14, 2013 at 3:54pm
No. I used your answer and showed that no matter what x,z,w are, the expression you got will work for y. We eliminated x, remember?
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