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September 3, 2014

September 3, 2014

Posted by **Amy** on Saturday, September 14, 2013 at 12:36pm.

If the centrifuge diameter is 13.5m , what should be its rotation period to produce a centripetal acceleration of 4 g?

First of I used the formula a=-rw^2. the numbers i used for a were -4(9.8m/s^2). -r was 13.5m. after i plugged it into the formula to solve for w, i got w to be 1.70. then i plugged it into the formula v=2piR/T. My answer became 50 but its still telling me i did it wrong. Any help please??

- PHYSICS!!! -
**Elena**, Saturday, September 14, 2013 at 6:25pma=ω²R =(2π/T)²R =4g

T= πsqrt(R/g)= 3.7 s

- PHYSICS!!! -
**Amy**, Saturday, September 14, 2013 at 7:25pmthe answer became 2.61 but im not sure how

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