Saturday

April 19, 2014

April 19, 2014

Posted by **<3** on Saturday, September 14, 2013 at 2:09am.

- Physics -
**Graham**, Saturday, September 14, 2013 at 4:49amGiven:

Let the first ball have height x, velocity u.

x(0) = 0[m]

u(0) = 23.2[m/s]

x(t) = x(0) + u(0) t + (g/2) t^2

.: x(t) = 23.2 t - 4.9 t^2

Let the second have height y, velocity v.

y(0) = 20[m]

v(0) = 0[m/s]

y(t) = y(0) + v(0) t + (g/2) t^2

.: y(t) = 20 - 4.9 t^2

Where: g = -9.8[m/s^2]

Find: t such that x(t)=y(t)

- Physics -
**<3**, Sunday, September 15, 2013 at 10:50pmI set the two position equations together and got 0.86 s as my time. Thanks!

**Related Questions**

physics - two students are on a balcony 20.6 m above the street. One student ...

physics - two students are on a balcony 20.6 m above the street. One student ...

physics - A ball is thrown from the top of a building upward at an angle of 66...

Physics - A red ball is thrown down with an initial speed of 1.3 m/s from a ...

physics - A red ball is thrown down with an initial speed of 1.2 m/s from a ...

Physics - a tennis ball is thrown vertically upward from the ground and the ...

Physics - A ball is thrown upward from the edge of a platform 15 m above the ...

science - The acceleration of gravity on the surface of Venus is 8.9m/s^2. Would...

physics - A ball rolls along a desktop with an uniform velocity of 3 m/s. What ...

physics - A ball rolls along a desktop with an uniform velocity of 3 m/s. What ...