Posted by christina on .
Eliminate the parameter to find a cartesian equation
x= 1t^2
y=t2
2 _<t _<2
known: 4 <(or=) y <(or =) 0
I got y= sq(x1)+2

MATH ASAP 
Graham,
Close.
Rearrange x = 1  t^2:
t = ±√(1x)
Substitute into: y = t  2
y = 2 ± √(1x)
Alternatively
Rearrange : y = t  2
t = y + 2
Substitute into x = 1  t^2
x = 1  (y+2)^2
Thus:
x = 3  4y  y^2