When setting the price of admission tickets for the amusement park, Tabitha wants the price for a two child, two- adult family to be $100. She also wants the adult tickets to cost $8 more than twice the cost of a child's ticket. How much should a child"s ticket cost?

2c + 2(2c+8) = 100

6c+16 = 100
c = 14

To solve this problem, let's break it down step by step.

Let's call the cost of a child's ticket "C" and the cost of an adult's ticket "A".

We know that the price for a two-child, two-adult family is $100. Since there are two children and two adults, the equation becomes:

2C + 2A = 100

We also know that the adult tickets should cost $8 more than twice the cost of a child's ticket. Mathematically, this can be represented as:

A = 2C + 8

Now, we can solve these two equations simultaneously to find the value of C, which represents the cost of a child's ticket.

Substituting the value of A from the second equation into the first equation, we get:

2C + 2(2C + 8) = 100

Simplifying the equation, we have:

2C + 4C + 16 = 100
6C + 16 = 100
6C = 100 - 16
6C = 84

Finally, dividing both sides of the equation by 6, we can find the value of C:

C = 84 / 6
C = 14

Therefore, a child's ticket should cost $14.