Posted by **Marco** on Wednesday, September 11, 2013 at 9:14pm.

You are creating a rectangular garden and want to surround it with brick edging. You also are going to divide it into two halves with the edging so that your vegetables and herbs are on one side and flowers are on the other.

You only have 120 ft worth of brick edging and want to enclose the most are possible. Determine the dimensions (Length and Width) that will maximize the total area of the garden, and state that maximum area

- Calculus -
**Steve**, Wednesday, September 11, 2013 at 11:59pm
you will have 2 strips of length x and 3 strips of length y.

2x+3y = 120

the area a is

a = xy = x(40 - 2/3 x) = 40x - 2/3 x^2

da/dx = 40 - 4/3 x

for max area, da/dx=0, so x = 30

Thus y=20, and the edging is evenly divided between width and length.

max area is thus 600 ft^2

## Answer This Question

## Related Questions

- Math - A rectangular garden bed is 3 2/3 ft by 4 1/2 ft. Bricks that are 1/2 ft ...
- Calculus - A gardener has a rectangular plot of land bordered on one side by a ...
- Pre-Calculus - A gardener has 72' of edging. She wants to use it to enclose a ...
- Pre-Calculus - A gardener has 100' of edging. She wants to use it to enclose a ...
- calculus - A landscape architect wishes to enclose a rectangular garden on one ...
- Pre Calculas - A GARDENER HAS 60' of edging. She wants to use it to enclose a ...
- College Math - 5) A landscaper wants to make a small planter and surround it ...
- Algebra - Rose wants to plant a garden. She made an outline in her yard of a ...
- 5th grade math - Meg is making ribbons for the country fair. she needs to glue ...
- calculus - A landscape architect wished to enclose a rectangular garden on one ...

More Related Questions