trig
posted by Luna on .
How do you solve sin(e^x)=0 for x?
The question is "find the smallest number x such that sin(e^x)=0".... but I can't even get AN answer lol!
Much appreciated!

well, sine is zero at zero radians, and at PI radians
e^x=0
because e^x cannot be zero, then
e^x=PI take the ln of each side
x=ln(PI)