Suppose a car is traveling at +22.3 m/s, and the driver sees a traffic light turn red. After 0.351 s has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at 8.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?

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To find the stopping distance of the car, we need to break down the problem into three parts: the initial velocity of the car, the time it takes for the driver's reaction, and the deceleration of the car.

1. Initial Velocity:
The question states that the car is traveling at +22.3 m/s. Since we are given the velocity, this is our initial velocity (u) in this case.

2. Time of Reaction:
After 0.351 seconds, the driver reacts to the red light and applies the brakes. This reaction time is denoted as time (t) in this case.

3. Deceleration:
The car then decelerates at a rate of -8.00 m/s^2. Since deceleration is negative, it opposes the motion and slows the car down. This deceleration is denoted as acceleration (a) in this case.

Now, to find the stopping distance, we can calculate it using the following formula:

stopping distance (s) = initial velocity (u) * time of reaction (t) + (1/2) * acceleration (a) * (time of reaction (t))^2

Let's substitute the values we have into the formula and calculate the stopping distance:

s = (22.3 m/s) * (0.351 s) + (1/2) * (-8.00 m/s^2) * (0.351 s)^2

s = 7.8173 m + (1/2) * (-8.00 m/s^2) * 0.123201 s^2

s = 7.8173 m - 0.98721 m

s ≈ 6.83 m

Therefore, the stopping distance of the car, as measured from the point where the driver first notices the red light, is approximately 6.83 meters.