Posted by **MS** on Wednesday, September 11, 2013 at 5:21am.

Find arc length of y=logx from x=1 to x=2.

dy/dx)^2=1/x^2

arc length=Int of [sqrt(1+1/x^2)]dx

=Int of [sqrt(1+x^2)/x^2]

=Int of [sqrt(1+x^2)]/x from x=1 to x=2.

How to proceed further to integrate?

## Answer This Question

## Related Questions

- Calculus - Find arc length of y=logx from x=1 to x=2. dy/dx)^2=1/x^2 arc length=...
- calculus - Find complete length of curve r=a sin^3(theta/3). I have gone thus- (...
- Calculus - Graph the curve and find its exact length. x = e^t + e^-t, y = 5 - 2t...
- Calculus - Can someone help me to evaluate these two integrals? INT dx/(x^2*sqrt...
- Calc - f(x,y,z) = y; W is the region bounded by the plane x+y+z=2;cylinder x^2+z...
- Calculus - Integral of dx/{(x+1)sqrt(x^2+4x+2)} is given as -arcsinh{(x+2)/(...
- AP Calc B/C - Find the arc length of one arch of the sine curve. I started it by...
- CALCULUS 2!!! PLEASE HELP!! - I'm having trouble with this question on arc ...
- calculus - Find the length of the arc formed by y = (1/8)(4x^2-2ln(x)) from x=4 ...
- calculus - Find circumference of the circle r=2acos theta. s= Int (0 to 2pi) of ...

More Related Questions