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posted by bryan on Tuesday, September 10, 2013 at 8:26pm.

Find the limit of the sequence {√(2), √(2√(2)), √(2√(2√(2))),...

if you consider the "last" term as x = √(2√(2√(2√(2....))) then x^2 = 2√(2√(2√(2√...))) = 2x x = 2

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