A rectangle shares a side with a square of area 32 and shares another side with a square of area 98. Waht is the area of the rectangle?
Are you sure that the squares have areas of 32 square units and 98 square units?
yes, that's the numbers I have for this question.
I tried solve it and now I have the answer
area of square 1 = 32, so square root of 32 will give the one side of 5.6568424
area of square 2 = 98, so square root of 98 will give the one side of 9.8994936
so thea area of the rectangle would be
length X width which is 56
Right.
To find the area of the rectangle, we need to determine the lengths of its sides. Let's call the length of the shared side between the rectangle and the square of area 32 as 'x', and the length of the shared side between the rectangle and the square of area 98 as 'y'.
We know that the area of a square is equal to the square of its side length. So, we have the equation:
x^2 = 32
By taking the square root of both sides of the equation, we find:
x = √32
Simplifying the square root of 32, we get:
x ≈ 5.66
Similarly, for the other square:
y^2 = 98
Taking the square root of both sides, we get:
y = √98
Simplifying the square root of 98, we have:
y ≈ 9.90
Now that we have the lengths of the shared sides, we can find the area of the rectangle. The area of a rectangle is given by the product of its length and width. In this case, the shared side 'x' will be considered as the width of the rectangle, and the shared side 'y' will be considered as the length. Therefore, the area of the rectangle is:
Area = x * y
= (5.66) * (9.90)
≈ 56.034
Hence, the area of the rectangle is approximately 56.034 square units.