100. G of a metal required 848 calories to be heated from 25 degrees celsius to 100 degrees celsius calculate the specific heat of the metal
848 cal = mass x specific heat x (Tfinal-Tinitial)
Substitute and solve for sp.h.
To calculate the specific heat of the metal, we need to use the formula:
Q = mcΔT
Where:
Q is the amount of heat energy absorbed by the metal (in calories),
m is the mass of the metal (in grams),
c is the specific heat capacity of the metal (in calories/gram·°C), and
ΔT is the change in temperature (in °C).
In this case, we are given:
Q = 848 calories,
m = 100 grams,
ΔT = (final temperature - initial temperature) = (100°C - 25°C) = 75°C.
Plugging in these values into the equation, we get:
848 calories = 100 grams * c * 75°C
To find the specific heat capacity (c), we can rearrange the equation and solve for c:
c = Q / (m * ΔT)
c = 848 calories / (100 grams * 75°C)
c ≈ 0.1133 calories/gram·°C
So, the specific heat of the metal is approximately 0.1133 calories/gram·°C.