posted by kenny contreras .
While following the directions on a treasure map, a pirate walks 38.8 m north, then turns and walks 5.8 m east.
What is the magnitude of the single straight-line displacement that the pirate could have taken to reach the treasure?
Answer in units of m
At what angle with the north would he have to walk?
Answer in units of ◦
a. D^2 = X^2 + Y^2
D^2 = 5.8^2 + 38.8^2 = 1539.1
D = 39.2 m.
b. tan A = Y/X = 38.8/5.8 = 6.68966
A = 81.5o, CCW.
A = 90-81.5 = 8.5o East of North.