m(0,3)

n(6,0)
p(0,-3)

scale factor=-1/3

how do you do this i have to draw the image of the figure with given vertices under the dilation with the given scale factor centered at the origin

multiply each coordinate value by -1/3

m(0,3) -> m'(0,-1)
etc.

oh ok thank you

wait how did you divide 0 divided by -0.33333333333

To draw the image of the figure under a dilation with a given scale factor, centered at the origin, you can follow these steps:

1. Plot the original figure using the given vertices. In this case, plot the points m(0,3), n(6,0), and p(0,-3) on a coordinate plane.

2. Determine the dilation of each vertex by multiplying the x-coordinate and y-coordinate of each point by the scale factor. In this case, the scale factor is -1/3.

For point m(0,3):
- Multiply the x-coordinate 0 by -1/3, which equals 0. (0 * (-1/3) = 0)
- Multiply the y-coordinate 3 by -1/3, which equals -1. (3 * (-1/3) = -1)
The image of point m(0,3) under the dilation is (0,-1).

For point n(6,0):
- Multiply the x-coordinate 6 by -1/3, which equals -2. (6 * (-1/3) = -2)
- Multiply the y-coordinate 0 by -1/3, which equals 0. (0 * (-1/3) = 0)
The image of point n(6,0) under the dilation is (-2,0).

For point p(0,-3):
- Multiply the x-coordinate 0 by -1/3, which equals 0. (0 * (-1/3) = 0)
- Multiply the y-coordinate -3 by -1/3, which equals 1. (3 * (-1/3) = 1)
The image of point p(0,-3) under the dilation is (0,1).

3. Plot the image of each vertex obtained from step 2 on the coordinate plane. In this case, plot the points (0,-1), (-2,0), and (0,1).

4. Connect the corresponding vertices of the original figure and the image. In this case, connect m(0,3) with its image (0,-1), n(6,0) with its image (-2,0), and p(0,-3) with its image (0,1).

5. The result is the image of the original figure after the dilation with the given scale factor centered at the origin.

Remember, a scale factor of -1/3 means that the image will be reduced in size by a factor of 1/3 in both the x and y directions from the original figure.