Suppose that it takes exactly 17.0 hr to drain a container of 6.20 liters of water. What is the average mass flow rate (in kilograms/second) of water from the container? Assume that the density (mass/volume) of water is exactly 1 g/cm^3.

To find the average mass flow rate of water from the container, we need to determine the total mass of water drained and divide it by the time taken to drain it.

First, let's find the mass of the water in the container. We know that the density of water is 1 g/cm^3, and we have 6.20 liters of water. Since 1 cm^3 is equal to 1 gram, we can convert the volume to grams by multiplying it by 1000:

Mass of water = 6.20 liters * (1000 g/liter) = 6200 grams

Next, we need to convert the mass to kilograms:

Mass of water = 6200 grams * (1 kilogram/1000 grams) = 6.20 kilograms

Now, we can calculate the average mass flow rate by dividing the mass by the time:

Average mass flow rate = 6.20 kilograms / 17.0 hours

However, the flow rate is typically measured in seconds rather than hours. So, let's convert the time to seconds:

17.0 hours * (3600 seconds/hour) = 61,200 seconds

Now, we can calculate the average mass flow rate in kilograms per second:

Average mass flow rate = 6.20 kilograms / 61,200 seconds

Simplifying the equation:

Average mass flow rate ≈ 0.000101 kg/s

Therefore, the average mass flow rate of water from the container is approximately 0.000101 kilograms per second.

Relationships or information needed:

Density of water=1g/cm^3
3,600s=1hr
1L=1 m^3=10^3 cm^3
1kg=10^3g

Solve for seconds in 17hr:

17hr*(3600s/1hr)=seconds

6.20L*(1 m^3/1L)*(10^3 cm^3/1m^3)=6.20 x 10^3 cm^3

Solve for mass of water:

Density=mass/volume

So, density*volume=mass

(1g/cm^3)*(6.20 x 10^3 cm^3)=mass of water

Solve for mass flow rate:

mass flow rate=mass of water/seconds