A real estate salesperson bought promotional calendars and date books to give to her customers at the end of the year. The calendars cost $0.75 each, and the date books cost $0.40 each. She ordered a total of 600 promotional items and spent $380. How many of each item did she order?

anyone...?

To find out how many of each item the salesperson ordered, we can set up a system of equations.

Let's represent the number of calendars she ordered as 'C' and the number of date books as 'D'.

We are given the following information:

1. The calendars cost $0.75 each, so the total cost of calendars would be 0.75C.
2. The date books cost $0.40 each, so the total cost of date books would be 0.40D.
3. The total number of promotional items ordered is 600, so the sum of C and D must be 600: C + D = 600.
4. The total amount spent is $380, so the sum of 0.75C and 0.40D must be 380: 0.75C + 0.40D = 380.

Now, we can solve this system of equations to find the values of C and D.

One way to solve it is by substitution:

1. Solve equation (3) for C: C = 600 - D.
2. Substitute this value for C in equation (4): 0.75(600 - D) + 0.40D = 380.
3. Simplify and solve for D: 450 - 0.75D + 0.40D = 380. Simplifying further, we have 450 - 0.35D = 380. Rearranging the equation, we get -0.35D = -70. Dividing both sides by -0.35, we find D = 200.

Now that we have the value of D, we can substitute it back into equation (3) to find the value of C:

C + 200 = 600.
C = 600 - 200.
C = 400.

So, the real estate salesperson ordered 400 calendars (C) and 200 date books (D).