find the area enclosed by the given curves.

y=squareroot of x
y=x/2
x=9

* i just graph it but do not know how to set it up the equation or anything.

I think there's a typo here. The curves intersect at (0,0) and (4,2). Going out to x=9 is bogus, unless you want to add up two areas.

Think of the area as a lot of small rectangle, each of width dx and height the distance between the curves.

a = ∫[0,4] √x - x/2 dx
a = 2/3 x^3/2 - 1/4 x^2 [0,4]
= (2/3 * 8 - 1/4 * 16)-(0)
= 16/3 - 4
= 4/3

If you really want to go out to x=9, then add the area, swapping which curve is on top:

add on ∫[4,9] x/2 -√x dx