posted by miley on .
A projectile is fired with an initial velocity of v0 feet per second. The projectile can be pictured as being fired from the origin into the first quadrant, making an angle O with the positive x-axis. If there is no air resistance, then at t seconds the coordinates of the projectile are x=v0(t)(cos O) and y=-16t^2+v0(t)(sin O). suppose a projectile leaves the gun at 100 ft/sec and O=60 degrees.
A) what are the coordinates of the projectile at time t=4 sec?
b)For how many seconds is the projectile in the air?
c)How far fro the gun does the projectile land?
d)What is the max height attained?
e)find an expression in terms of v0 and O for the time in the air
f)find an expression in terms of v0 and O for the distance from the gun
g) Find an expression in terms of v0 and O for the maximum height
h) show that y= ((-16sec^2O)/(v0)^2)(x^2)+xtanO
See previous post: Sun,11:33 AM.