Tuesday

April 28, 2015

April 28, 2015

Posted by **SS01** on Sunday, September 8, 2013 at 6:28am.

(a) What is the inner product of the 3rd row and 14th row of this matrix?

b) What is the inner product of the 3rd row with itself?

C) Suppose we have a quantum circuit that takes the input |0> and outputs |+>, and also takes the input |1> and outputs −|−>. If we input √2*i/√3|+> + 1/√3|−>, what does the circuit output?

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**Anonymous**, Sunday, September 8, 2013 at 11:42pmAny luck with the rest of the questions?

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**SS01**, Monday, September 9, 2013 at 12:20amyup, i got few questions, like 2 , 6 ,7 ,8

what about you?

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**SS01**, Monday, September 9, 2013 at 12:28amanybody please help

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**Anonymous**, Monday, September 9, 2013 at 1:02amGot 7 and 8 for the moment!

can you help with the rest?

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**SS01**, Monday, September 9, 2013 at 1:04amya.....but i need more question's answers to get 80%

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**Anonymous**, Monday, September 9, 2013 at 1:40amgetstudyroom(dot)com/course/43483#

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**SS01**, Monday, September 9, 2013 at 2:14amwhat about answers?

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**Anonymous**, Monday, September 9, 2013 at 4:56amsomebody please answer this question....

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**Anonymous**, Thursday, September 12, 2013 at 2:55amfor c part i think the answer is 1/(sqrt3)for 0) and ((sqrt2)*i)/(sqrt3) for 1) ... i am not sure

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**Anonymous**, Thursday, September 12, 2013 at 8:57amdid anyone check with the above answer?

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**ss01**, Thursday, September 12, 2013 at 9:15amnope......no chance left any luck for 9 or 12?

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**Anonymous**, Thursday, September 12, 2013 at 1:04pmhelp needed even for q.4 ...anyone?

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**Anonymous**, Thursday, September 12, 2013 at 3:56pm1 ques ans pls..

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**Anonymous**, Friday, September 13, 2013 at 1:27amcan anyone tell me wats the ans of prob 2?

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**ss01**, Friday, September 13, 2013 at 2:56amany clue for 12, is it all 8?

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**Anonymous**, Friday, September 13, 2013 at 8:15amim missing 5 and 12 ..

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**ss01**, Friday, September 13, 2013 at 8:45ami tell you 5 and 12 you tell me 9

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**Help**, Friday, September 13, 2013 at 11:59amHelp for Q. No 6

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**ss01**, Friday, September 13, 2013 at 12:19pmi need 5 9 and 12 rest i will help

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**Help**, Friday, September 13, 2013 at 12:37pm6 then I will help with 5, 9 and 12

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**Help**, Friday, September 13, 2013 at 1:05pmLeave it.. Its not good to discuss exam questions outside. I don't know how i reached here.. i just realized i don't need course certificate, if I'm not worth it. So, I will try to solve it myself. You do too.. :)

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**Anonymous**, Friday, September 13, 2013 at 5:07pmC) 1/sqrt(3)|0> + (sqrt(2)*i)/sqrt(3)|1>

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**Anonymous**, Friday, September 13, 2013 at 5:53pmSS01: The answer to 12 is only 2.

I need 4 and 9.. can you give me the answers now?

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**Somebody**, Friday, September 13, 2013 at 7:40pmFor question 9 the answer is

CNOT12, CNOT23

Please give us the answer to question 4 and 6!

Thank you!

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**scholar**, Friday, September 13, 2013 at 9:54pm4a 0

4b 1

12 2

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**ank**, Saturday, September 14, 2013 at 5:38am1-10/36

can anyone tell me wats the ans of 2 nd 5?please

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**ank**, Saturday, September 14, 2013 at 5:47ammy ans C) 1/sqrt(3)|0> + (sqrt(2)*i)/sqrt(3)|1> is showing wrong..last attempt left..please help me

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**Test**, Saturday, September 14, 2013 at 5:47amHow to do Number 6?

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**arm**, Saturday, September 14, 2013 at 5:49amwhat is the answer of 11

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**rare**, Saturday, September 14, 2013 at 5:56amhow to find the state of the composite system in prob 2?? please ans

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**Somebody**, Saturday, September 14, 2013 at 5:56amank, The answer to question 5 is

1/(sqrt(3))

in the first box and

(2*i)/sqrt(6)

in the second box.

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**Somebody**, Saturday, September 14, 2013 at 5:59amrare, for q2 - just multiply the two quibits states.

Answer to q2:

1/sqrt(2)*3/5 ----> |00>

(3*i)/(5*sqrt(2)) ----> |01>

4/(5*sqrt(2)) -----> |10>

(4*i)/(5*sqrt(2)) -----> |11>

Please, give us answers to question 6! Thanks

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**ank**, Saturday, September 14, 2013 at 6:04amthanks..ans6- its 1 and 1/2

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**rare**, Saturday, September 14, 2013 at 6:09amthanks..6a-1,6b-1/2

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**Somebody**, Saturday, September 14, 2013 at 6:27amThank you ppl!

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**Anonymous**, Saturday, September 14, 2013 at 6:39amPlease help for 3,8 and 11

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**HERO**, Saturday, September 14, 2013 at 6:44amanoy, answer for 8 is

8(a)

1/sqrt(2) |00>

0 |01>

0 |10>

1/sqrt(2) |11>

8(b)

0 |00>

1/sqrt(2) |01>

-1/sqrt(2) |10>

0 |11>

8(c)

1/2 |00>

1/2 |01>

-1/2 |10>

1/2 |11>

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**HERO**, Saturday, September 14, 2013 at 6:47amanswer for Q3 is option 4

answer for Q11 is option 2

Please revert..........with thanks

and let me know if any help needed

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**Anonymous**, Saturday, September 14, 2013 at 7:25amthanks for help but Q3 and Q11 are false

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**HERO**, Saturday, September 14, 2013 at 7:33amany help for Q 3 and 11

I am not sure what to tick.......

sorry anoy.....it was just a assumption.

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**SB**, Saturday, September 14, 2013 at 8:04amwhat is the answer of 3?

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**Anonymous**, Saturday, September 14, 2013 at 12:55pmWhats the solution of Question 1???

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**SB**, Saturday, September 14, 2013 at 1:09pm1) 10/36 some help for Q3?

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**Anon**, Saturday, September 14, 2013 at 3:10pmany1 got the ans to q 10?

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**mark**, Saturday, September 14, 2013 at 4:44pmSomeone know answers for 7th and 10th? Attempts are finishing :(

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**Anon**, Saturday, September 14, 2013 at 4:52pmSomeone give me Q3 and I give him/her all the others questions!

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**mark**, Saturday, September 14, 2013 at 5:03pmAnon: 3rd choice foê Q3

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**mark**, Saturday, September 14, 2013 at 5:04pmAnon, please help with 7 and 10

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**Anon**, Saturday, September 14, 2013 at 5:15pm7)A) I,H

7)B) X,H

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**Anon**, Saturday, September 14, 2013 at 5:55pmANS TO 3 IS c

WATS Q10?

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**Lord**, Saturday, September 14, 2013 at 11:28pm@Anon, ans to question #10 is 1110

Can someone tell me the ans to question 5?

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**Anon**, Sunday, September 15, 2013 at 12:28am@ Lord

The circuit is a phase change (Z) with a Hadamard (H); plug in the eqn (simple arithmetic if u understand the material)

TY for ans tho, wish i knew how u arrived to it, i wrote out all the y's and i couldnt figure out s

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**HERO**, Sunday, September 15, 2013 at 5:29amQ11 answer please......

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**HERO**, Sunday, September 15, 2013 at 5:31amWhat is the superposition that results if you apply the Hadamard transform H⊗n to the state 12√(|0n⟩+|1n⟩)? (Here, |0n⟩:=|00⋯0n⟩ and |1n⟩:=|11⋯1n⟩.)

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**victor**, Sunday, September 15, 2013 at 10:33amanswer of q 3. is 3rd option

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**victor**, Sunday, September 15, 2013 at 10:51amanswer of q 2 is

3/(5*sqrt(2)) |00>

(3*i)/(5*sqrt(2)) |01>

4/(5*sqrt(2)) |10>

(4*i)/(5*sqrt(2)) |11>

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**noname**, Sunday, September 15, 2013 at 1:16pmanswer 0f question 11 is option no. 4 and it is correct one, sure.