an electron of energy 100 mev collides with a photon of wavelength 3*10^6 nm.what is the maximum energy loss suffered by the electron..

To find the maximum energy loss suffered by the electron in the given scenario, we need to calculate the energy of the photon that is absorbed by the electron. The energy of a photon can be found using the formula:

E = hc/λ

Where:
E is the energy of the photon
h is Planck's constant (approximately 6.626 x 10^-34 J·s)
c is the speed of light in vacuum (approximately 3 x 10^8 m/s)
λ is the wavelength of the photon

First, let's convert the given wavelength from nanometers (nm) to meters (m):
λ = 3 x 10^6 nm = 3 x 10^-3 m

Now, substituting the values into the formula, we can find the energy of the photon:

E = (6.626 x 10^-34 J·s)(3 x 10^8 m/s) / (3 x 10^-3 m)
E ≈ 6.626 x 10^-19 J

Since the electron is colliding with the photon, the maximum energy loss suffered by the electron will be equal to the energy of the absorbed photon. Therefore, the maximum energy loss suffered by the electron is 6.626 x 10^-19 J or 100 MeV (since 1 MeV is equal to 1.6 x 10^-13 J).