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Posted by on Saturday, September 7, 2013 at 3:04am.

Mno4- + So3-2 = Mno2 + sO4-2 (OH-) solve this redox reaction and give me the method also

  • chemistry - , Saturday, September 7, 2013 at 4:25am

    Balancing a red/ox reaction in basic aqueous solution in ten easy steps.

    1: Separate into Half Equations:
    MnO4{-} + _ = MnO2 + _
    SO3{2-} + _ = SO4{2-} + _

    2: Use water to balance O
    MnO4{-} + _ = MnO2 + 2 H2O + _
    SO3{2-} + H2O + _ = SO4{2-} + _

    3: Use H{+} to balance H
    MnO4{-} + 4 H{+} + _ = MnO2 + 2 H2O + _
    SO3{2-} + H2O + _ = SO4{2-} + 2 H{+} + _

    4: Neutralise H{+} with OH{-}
    MnO4{-} + 4 H2O + _ = MnO2 + 2 H2O + 4 OH{-}
    SO3{2-} + H2O + 2 OH{-} = SO4{2-} + 2 H2O + _

    5: Cancel superfluous water
    MnO4{-} + 2 H2O + _ = MnO2 + 4 OH{-}
    SO3{2-} + 2 OH{-} = SO4{2-} + H2O + _

    6: Balance charges with electrons
    MnO4{-} + 2 H2O + 3 e = MnO2 + 4 OH{-}
    SO3{2-} + 2 OH{-} = SO4{2-} + H2O + 2 e

    7: Balance electron counts and combine
    2 MnO4{-} + 3 SO3{2-} + 4 H2O + 6 OH{-} = 2 MnO2 + 3 SO4{2-} + 3 H2O + 8 OH{-}

    8: Cancel superfluous molecules and ions
    2 MnO4{-} + 3 SO3{2-} + H2O = 2 MnO2 + 3 SO4{2-} + 2 OH{-}

    9: ... Eight. That's eight.
    Balancing a red/ox reaction in basic solution in eight easy steps.

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