Thursday

August 21, 2014

August 21, 2014

Posted by **Kiki** on Saturday, September 7, 2013 at 2:47am.

- Math -
**Graham**, Saturday, September 7, 2013 at 2:51amThe equation of a line whose center is (a, b) and radius is c is:

(x-a)^2 + (y-a)^2 = c^2

- Math -
**Kiki**, Saturday, September 7, 2013 at 3:12amIs it (x-3)^2 + (y-1)^2 =16

- Math -
**Graham**, Saturday, September 7, 2013 at 4:30amNo, it's:

(x+3)^2 + (y-1)^2 = 16

- Math -
**Kiki**, Saturday, September 7, 2013 at 2:24pmThank you

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