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March 6, 2015

March 6, 2015

Posted by **Grant** on Saturday, September 7, 2013 at 1:37am.

Eureka's Age:

Renton's Age:

- Algebra, HELP IM CLUELESS -
**Bosnian**, Saturday, September 7, 2013 at 2:45amE = Eureka's Age

R = Renton's Age

E = R - 16

In 3 years Renton will be R + 3

Eureca will be E + 3

In 3 years Renton will be twice as old as Eureka.

This mean :

R + 3 = 2 ( E + 3 )

R + 3 = 2 ( R - 16 + 3 )

R + 3 = 2 ( R - 13 )

R + 3 = 2 R - 26 Add 26 to both sies

R + 3 + 26 = 2 R - 26 + 26

R + 29 = 2 R Subtract R to both sides

R + 29 - R = 2 R - R

29 = R

R = 29

E = R - 16

E = 29 - 16

E = 13

Eureka's Age = 13

Renton's Age = 29

Proof :

In 3 years Renton will be 32

Eureca will be 16

32 / 16 = 2

Renton will be twice as old as Eureka.

- Algebra, HELP IM CLUELESS -
**Graham**, Saturday, September 7, 2013 at 2:46amLet y be Eureka's age in years.

Let x be Renton's age in years.

So:

y = x-16

2(y+3) = x+3

Rearrange to express x as a function of y.

x = y + 16

x = 2y + 3

Eliminating x by equating:

y + 16 = 2y +3

=> y = 13

Substituting back to obtain x.

x = 13 + 16

=> x = 29

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