posted by Bec on .
you roll 2 dice. what is the probability that at least one of them is a 6.
Let A denote the event that one specific die is a 6.
Let B denote the event that the other die is a 6.
P(A) = 1/6
P(B) = 1/6
Note that the events are independent.
So we need to find: P(A˅B)
Use the exclusion principle:
P(A˅B) = P(A) + P(B) - P(A˄B)