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December 20, 2014

December 20, 2014

Posted by **Khelany** on Friday, September 6, 2013 at 11:31pm.

- Math -
**Graham**, Friday, September 6, 2013 at 11:50pmAssume that length l is greater than or equal to width w. Assert that the dividing fencing must be equal to the width (ie it must be perpendicular) by reasoning that if it were at any other angle, it would be longer, and the length would be reduced.

A = w * l

200 = 3w + 2l

.: A = w*(200-3w)/2

or A = 100 w - (3/2) w^2

Take the derivative and find when this is 0.

0 = (d/dw) (100 w-(3/2)w^2)

Solve for w, use to determine A

- Math -
**Anonymous**, Sunday, September 8, 2013 at 10:11amwhere did you get the 3w

- Math -
**Graham**, Tuesday, October 1, 2013 at 3:21amThe 200m fencing is used for two length-sides (l), two width-sides (w) and the middle divider (w).

This: 200 = 2l + 3w

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