Which of the following substances can exist in an optically active form
a) 1,3 dibromopropane
b) ethyl cyclohexane
c) 3 ethylpentane
http://www.jiskha.com/display.cgi?id=1216921105
To determine whether a substance can exist in an optically active form, we need to consider its molecular structure and symmetry. Optically active substances are chiral, which means that they have a non-superimposable mirror image.
a) 1,3-dibromopropane: This compound has a central carbon atom bonded to two bromine atoms and one methyl group on one side, and one hydrogen atom on the other side. It is not symmetric and can exist in optically active forms.
b) Ethyl cyclohexane: This compound consists of a cyclohexane ring with an ethyl group attached. The cyclohexane ring has a plane of symmetry, meaning it is symmetrical and can exist in optically inactive forms.
c) 3-ethylpentane: This compound has a pentane chain with an ethyl group attached. It does not have a chiral carbon atom and lacks a non-superimposable mirror image. Therefore, it can exist only in optically inactive forms.
In summary, the substance that can exist in an optically active form is a) 1,3-dibromopropane.