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March 28, 2017

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A car is traveling at 95km/hr. the driver steps on the brakes and the car comes to a stop in 60m. What is the car's deceleration?

  • physics - ,

    Vi = 95,000m/3600 s = 26.4 m/s
    v = Vi - a t
    v = 0 at end of trip
    0 = 26.4 - a t so t = 26.4/a

    x = Vi t - .5 a t^2
    60 = 26.4 t - .5 a t^2

    60 = 26.4 (26.4/a) -.5 (a)(26.4^2)/a^2

    60 = .5 (26.4)^2/a

    a = 5.8 m/s^2 is deacceleration

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