Thursday

April 24, 2014

April 24, 2014

Posted by **HELP** on Thursday, September 5, 2013 at 5:11pm.

I know that standard is y=ax^2+bx+c obviously, since the points are on the graph we know x and y so a,b and c need to be found. The vertex is on (4,-4) the points on the left side of the parabola from the vertex up are (3,-3) (2,0) and (1,5). On the right side upwards from the vertex is (5,3) (6,0) and (7,5) I started at the origin to find all the points so if u plot them all and draw te curved lines u will have what I have. Now what do I do???

- Algebra 1 parabola's -
**Reiny**, Thursday, September 5, 2013 at 6:03pmfrom the vertex (4,-4)

we can say that parabola must be

y = a(x-4)^2 -4

to find the value of a, let's use one of the other points

e.g. 1,5)

5 = a(-3)^2 - 4

9 = 9a

a = 1

so the parabola is

y = (x-4)^2 -4 or

y = x^2 - 8x + 12

I will leave it up to you to make sure all those other points we did not use are also on this curve by subbing them into our equation.

They should all satisfy the equation,

e.g. I will use (7,5)

LS = 5

RS = 49 - 56 + 12 = 5 = LS

so far so good!

- Algebra 1 parabola's -
**Taylor**, Thursday, September 5, 2013 at 6:11pmThanks so much!!!

**Related Questions**

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...

Parabola Help - by plotting the graph of parabola y=2+3x-2x^2 which 3 option are...

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...

Algebra: Parabolas - I have a math problem that requires me to find the focal ...

algebra - 6. Find the equation of each parabola described below. a) parabola ...

Algebra 2 - Point (-6,-2) lies on a parabola that has its vertex at (0,1). Write...

Algebra - Consider the graph of the equation y=ax^2+bx+c, when a does not equal ...

precalculus - graph the parabola y=2x^2-6x-3. plot point on the parabola A[1,-7...

Algebra - I'm trying this again, I'd like the quadratic form, so i can then work...

Math - determine vertex, focus and directrix of parabola. then graph the ...