Friday

August 1, 2014

August 1, 2014

Posted by **Anonymous** on Thursday, September 5, 2013 at 5:07pm.

If the train decelerates at a uniform rate of 1.3m/s2 and, after the stop, accelerates at a rate of 0.70m/s2 , how much time is lost because of stopping at the station?

- physics -
**Henry**, Friday, September 6, 2013 at 7:47pmVo = 74km/h = 74000m/3600s = 20.56 m/s.

V = Vo + a*t

t1 = (V-Vo)/a = (0-20.56)/-1.3 = 15.8 s.

t2 = 3 min = 180 s.

t3 = 20.56-0)/0.7 = 29.37 s

T=t1 + t2 + t3=15.8 + 180 + 29.37=225.2s

= 3.75 min. = Time lost.

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