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July 28, 2014

July 28, 2014

Posted by **Ë̤T̤̈Ẅ̤ä̤z̤̈Ḧ̤ë̤r̤̈ë̤ ⍨** on Thursday, September 5, 2013 at 3:50pm.

side a=wm b=8m and c=(w+4)m (on the picture)

I'm guessing u use the formula surface area=2ab+2bc+2ac??? Well if so I need all that solved into y=ax*2+bx+c so I can solve step (b) and (c) for (b) I have to Use the discriminate to determine the number of values of w in the equation from part (a). I can do that and part c. Many thanks for your help!!!

- Geometry / Algebra 1 -
**Reiny**, Thursday, September 5, 2013 at 5:51pmWe can't see your picture, but from your formula

surface area=2ab+2bc+2ac

I will surmise the you have a rectangular prism.

surface area=2ab+2bc+2ac

= 2(wm)(8m) + 2(8m)(w+4) + 2(wm)(W+4) = 314

16 wm^2 + 16wm + 64m + 2mw^2 + 8wm = 314

Since we want to solve for w, let's consider this to be a quadratic equation in w

2m w^2 + w(16m^2 + 16m + 8m) + 64m - 314 = 0

so comparing this to ax^2 + bx + c = 0

a = 2m , b = (16m^2 + 24m) , and c = 64m-314

the discriminant = b^2 - 4ac

= ...

you said you could do that.

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