A steam catapult launches a jet aircraft from the aircraft carrier John C. Stennis, giving it a speed of 190 mi/h in 2.70 s.

a.) Find the average acceleration of the plane.
b.) Assuming the acceleration is constant, find the distance the plane moves.

avg a = 190mph/2.70s = 70.37mi/(hr•s)

Convert that to the units of choice (probably ft/s) and then
s = 1/2 a*2.7^2

To find the average acceleration of the plane, we use the formula:

Acceleration (a) = (Final Velocity - Initial Velocity) / Time

Given:
Initial Velocity (v0) = 0 mph (since the plane is initially at rest)
Final Velocity (v) = 190 mph
Time (t) = 2.70 s

Substituting the values into the formula, we get:

Acceleration (a) = (190 mph - 0 mph) / 2.70 s

Simplifying, we find:

Acceleration (a) = 70.4 mph/s

Therefore, the average acceleration of the plane is 70.4 mph/s.

Now, to find the distance the plane moves, we can use the kinematic equation:

Distance (d) = Initial Velocity × Time + (1/2) × Acceleration × Time^2

Since the initial velocity is 0 mph, we can further simplify the equation to:

Distance (d) = (1/2) × Acceleration × Time^2

Substituting the values we know:

Distance (d) = (1/2) × 70.4 mph/s × (2.70 s)^2

Calculating, we get:

Distance (d) = 255.2 miles

Therefore, assuming constant acceleration, the plane moves a distance of 255.2 miles.