Posted by **leena** on Thursday, September 5, 2013 at 1:19pm.

in the diagram AB=20 cm, BC=21 cm, AD=10 cm and DE= 10.5 cm. Angles ABC and ADE are right angles. if triangleADE is removed from triangleABC.What is the area of shaded region that remains?

- geometry -
**Graham**, Friday, September 6, 2013 at 9:20am
Missing information: presumably A, D, B are colinear.

For right angle XYZ, |∆XYZ|=(1/2)(XY×YX)

So:

|∆ABC|-|∆ADE| = (1/2)(AB×BC)-(1/2)(AD×DE)

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