Harold has been given this list of equivalent fractions:6/14,12/28,3/7.He is supposed to choose the fraction that is in simplest form.Which one should Harold choose?

The numerator and the denominator of --

6/14 are divisible by 2
12/28 are divisible by 4
3/7 aren't divisible by anything but 1.

To determine which fraction is in simplest form, we need to find the fraction with the smallest numerator and denominator. Let's simplify each fraction:

1. To simplify 6/14, we can divide both the numerator and denominator by their greatest common divisor, which is 2. So, 6/14 simplifies to 3/7.

2. To simplify 12/28, we can also divide both the numerator and denominator by 4, which is their greatest common divisor. So, 12/28 simplifies to 3/7.

3. The fraction 3/7 is already in its simplest form.

Therefore, Harold should choose the fraction 3/7, as it is already in simplest form.

To determine which fraction is in simplest form, we need to find the fraction that cannot be further reduced. The simplest form of a fraction is when the numerator and denominator do not have any common factors other than 1.

To simplify fractions, one approach is to find the greatest common divisor (GCD) or highest common factor (HCF) of the numerator and denominator and then divide both the numerator and denominator by it.

Let's simplify each of the given fractions given:

1. 6/14: The GCD of 6 and 14 is 2. By dividing both numerator and denominator by 2, we get 3/7.

2. 12/28: The GCD of 12 and 28 is 4. By dividing both numerator and denominator by 4, we get 3/7.

3. 3/7: The numerator and denominator do not have any common factors other than 1, so this fraction is already in its simplest form.

Comparing the fractions, we can see that the fraction 3/7 appears twice in the list. Therefore, Harold should choose the fraction 3/7 as it is in simplest form.