A boy sledding down a hill accelerates at 1.55 m/s2. If he started from rest, in what distance would he reach a speed of 6.90 m/s?

To find the distance the boy would travel, we can use the equations of motion. Specifically, we can use the equation:

v^2 = u^2 + 2as

Where:
- v is the final velocity (6.90 m/s)
- u is the initial velocity (0 m/s, since he started from rest)
- a is the acceleration (1.55 m/s^2)
- s is the distance we want to find

Rearranging the equation, we have:

s = (v^2 - u^2) / (2a)

Substituting the given values, we have:

s = (6.90^2 - 0^2) / (2 * 1.55)

Calculating this expression, we get:

s = 23.697 m

Therefore, the boy would reach a speed of 6.90 m/s in a distance of approximately 23.697 meters.

s = v^2 / 2a

just plug in the values