This question has to do with kinematics graphing. I CAN NOT REPRODUCE THE GRAPH BUT hope that some help can be given to me with this question.

The position versus time for a certain object moving along the x-axis. The object's initial position is -2 m. Find the instantaneous velocity at 2 s. Answer in m/s

At time zero, position -2. The rest depends on the velocity. Just compute postion based on

x=xi + v*time

instantaneous velocity is the slope of the position vs time at t=2.

examples
http://dev.physicslab.org/Document.aspx?doctype=5&filename=Kinematics_ConstantVelocityPositionTimeGraphs1.xml

http://www.physicsclassroom.com/mmedia/kinema/fs.cfm

http://hyperphysics.phy-astr.gsu.edu/hbase/mechanics/motgraph.html

To find the instantaneous velocity at 2 seconds, you need to use the given position versus time graph.

First, you need to know that velocity is the derivative of position with respect to time. In other words, it is the rate of change of position with respect to time. Mathematically, velocity is calculated as v = Δx/Δt, where Δx represents the change in position and Δt represents the change in time.

Since you have a position versus time graph, you can find the instantaneous velocity at a specific time by finding the slope of the tangent line to the graph at that time.

Now, let's break down the steps to find the instantaneous velocity at 2 seconds:

Step 1: Identify the position of the object at 2 seconds on the graph.
Step 2: Determine the position at an earlier time (let's say, t1) and a later time (t2) close to 2 seconds.
Step 3: Calculate the change in position by subtracting the earlier position from the later position: Δx = x2 - x1.
Step 4: Calculate the change in time by subtracting the earlier time from the later time: Δt = t2 - t1.
Step 5: Use the values of Δx and Δt in the velocity formula: v = Δx/Δt.

In this specific case, since you cannot reproduce the graph, it is not possible to determine the exact positions at earlier and later times. Therefore, it is not possible to calculate the instantaneous velocity at 2 seconds just based on the given information.

However, if you provide additional information about the shape or behavior of the graph, I can assist you in finding the instantaneous velocity more accurately.