A sports car moving at constant velocity travels 130m in 4.7s, what is the magnitude of acceleration if car brakes at 4.4m?

what does "brakes at 4.4m" mean?

I believe the car brakes for 4.4 sec.

To calculate the magnitude of acceleration when the car brakes, we need to determine the change in velocity and the time it takes to come to a stop.

Given information:
Distance traveled (d) = 130m
Time taken (t) = 4.7s
Final braking distance (s) = 4.4m

First, we need to calculate the initial velocity (u) of the car. Since it is moving at a constant velocity, there is no acceleration during the initial 130m.

Using the formula:
u = (d - s) / t

u = (130m - 4.4m) / 4.7s
u = 125.6m / 4.7s
u ≈ 26.7 m/s

Now, we can calculate the acceleration (a) using the formula:
a = (v - u) / t

Since the car comes to a stop, the final velocity (v) is 0 m/s.

a = (0 m/s - 26.7 m/s) / 4.7s
a = -26.7 m/s / 4.7s
a ≈ -5.68 m/s²

The magnitude of acceleration is the absolute value of the calculated acceleration:
Magnitude of acceleration ≈ | -5.68 m/s² | = 5.68 m/s²

Therefore, the magnitude of acceleration when the car brakes is approximately 5.68 m/s².