A helicopter is ascending vertically with a speed of 5.03m/s . At a height of 132m above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground?

the height

h = 132 + 5.03t - 4.9t^2
solve for t when h=0

To find the time it takes for the package to reach the ground, we can use the equation for free fall motion:

h = (1/2)gt^2

Where h is the vertical displacement (132m in this case), g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and t is the time.

In this scenario, the initial velocity of the package is 0 m/s since it is dropped from rest.

Using the equation, we can rearrange it to solve for time:

t = sqrt((2h)/g)

Plugging in the values:

t = sqrt((2 * 132) / 9.8)

t ≈ sqrt(26.9388)

t ≈ 5.19 seconds

Therefore, it takes approximately 5.19 seconds for the package to reach the ground.