Tuesday
September 2, 2014

Homework Help: Maths

Posted by MS on Wednesday, September 4, 2013 at 1:47am.

Eq of curve is y=b sin^2(pi.x/a). Find mean value for part of curve where x lies between b and a.

I have gone thus far-
y=b[1-cos(2pi x/a)/2]/2
Integral y from a to b=b/2(b-a)-ab/4pi[sin(2pi b/a)-sin2pi)

MV=b/2-[ab sin(2pi b/a)]/(b-a)
Ans given is b/a. I am not getting further.

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