Posted by **MS** on Wednesday, September 4, 2013 at 1:47am.

Eq of curve is y=b sin^2(pi.x/a). Find mean value for part of curve where x lies between b and a.

I have gone thus far-

y=b[1-cos(2pi x/a)/2]/2

Integral y from a to b=b/2(b-a)-ab/4pi[sin(2pi b/a)-sin2pi)

MV=b/2-[ab sin(2pi b/a)]/(b-a)

Ans given is b/a. I am not getting further.

- Maths -
**Graham**, Wednesday, September 4, 2013 at 3:36am
y(x) = b sin^2(πx/a)

The mean of the curve over the range b to a is:

y_ave = 1/(a-b) ∫(x=b to a) y(x) dx

sin^2(πx/a) = 1 - cos(2πx/a)

∫y(x) dx

= (b/2) ∫ (1 - cos(2πx/a)) dx

= (b/2) (x - a sin(2πx/a)/(2π)) + constant

= bx/2 - ab sin(2πx/a)/(4π) + constant

∫(x=b to a) y(x) dx

= b(a-b)/2 + ab sin(2πb/a)/(4π)

1/(a-b)∫(x=b to a) y(x) dx

= (b/2) + (ab sin(2πb/a))/(4π(a-b))

- Maths -
**Graham**, Wednesday, September 4, 2013 at 3:39am
And, that is just about as far as it goes. You can play around with the sine identities, but it doesn't simplify much further.

- Maths -
**MS**, Wednesday, September 4, 2013 at 3:52am
Does it indicate that the answer 'b/a' given in the book may be wrong? I tried many times but could not get it.

## Answer this Question

## Related Questions

- calculus - Find complete length of curve r=a sin^3(theta/3). I have gone thus- (...
- calc - i did this problem and it isn't working out, so i think i'm either making...
- Integration by Parts - integral from 0 to 2pi of isin(t)e^(it)dt. I know my ...
- maths - Please can you help me with this question? Choose the option which is a ...
- Math - 1. On the interval [0, 2pi] what are the solutions to the equation ...
- Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...
- Integral - That's the same as the integral of sin^2 x dx. Use integration by ...
- Calc - Find the exact total of the areas bounded by the following functions: f(x...
- math - Evaluate. 1. sin^-1(-1/2) 2. cos^-1[(-root 3)/2] 3. arctan[(root3)/3] 4...
- Calculus - Breathing is cyclic and a full respiratory cycle from the beginning ...