How many liters is 5.8 moles of neon (Ne) at STP?
1 mol of any gas at STP occupies 22.4L.
To determine the number of liters for 5.8 moles of neon (Ne) at STP, we need to use the ideal gas law equation, which is:
PV = nRT
Where:
P represents pressure (in atmospheres)
V represents volume (in liters)
n represents the number of moles
R is the ideal gas constant (0.0821 L·atm/(mol·K))
T represents temperature (in Kelvin)
At STP (standard temperature and pressure), the conditions are:
Pressure (P) = 1 atmosphere
Temperature (T) = 273.15 Kelvin
Now we can rearrange the ideal gas law equation to solve for volume (V):
V = (nRT) / P
Let's plug in the values:
n = 5.8 moles
R = 0.0821 L·atm/(mol·K)
P = 1 atmosphere
T = 273.15 Kelvin
V = (5.8 moles * 0.0821 L·atm/(mol·K) * 273.15 Kelvin) / 1 atmosphere
Calculating this equation gives us:
V ≈ 13.55 liters
Therefore, 5.8 moles of neon at STP is approximately equal to 13.55 liters.